(3n^2-1/7n^2+n+2)-3/7

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Solution for (3n^2-1/7n^2+n+2)-3/7 equation: 


n in (-oo:+oo)

3*n^2-((1/7)*n^2)+n-(3/7)+2 = 0

3*n^2+(-1/7)*n^2+n-3/7+2 = 0

20/7*n^2+n+11/7 = 0

DELTA = 1^2-(11/7*20/7*4)

DELTA = -831/49

DELTA < 0

n belongs to the empty set

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